Hydro Energy from Flow Duration
Converts a simple flow‑duration breakdown (discharge classes and share of the year) into annual energy for a run‑of‑river or storage plant, given net head, efficiency and turbine discharge limit.
Inputs (SI units)
| # | Q (m³/s) | % of year |
|---|---|---|
| 1 | ||
| 2 | ||
| 3 | ||
| 4 | ||
| 5 |
Summary
Enter net head, efficiency, turbine discharge limit and a few flow classes (Q and share of the year). Click Compute energy to see the annual energy per class, total annual energy, installed capacity and capacity factor.
Profile, table & exports
Energy contribution by flow class
Bars show how much each flow class contributes to annual energy (MWh/year). Turbine discharge limit caps the used flow; any excess is treated as spill.
| Flow Q | % of year | Hours/yr | Turbine Qused | Spill Q | Power used | Energy used |
|---|---|---|---|---|---|---|
| No results yet. | ||||||
Theory (brief)
Instantaneous power for one unit (SI units):
P = ρ g Q H η, internally converted to kW using
ρ g ≈ 9.81 kN/m³ so
P [kW] = 9.81 · Q · H · η.
For each flow class i with discharge Qi
and share of the year fi (%):
- Hours per year:
ti = (fi / 100) · 8760(h/yr) - Effective turbine flow
(capped by turbine limit
Qt,max):
Qi,used = min(Qi, Qt,max) - Spill flow:
Qi,spill = max(0, Qi − Qi,used) - Power used at that class:
Pi = 9.81 · Qi,used · H · η(kW) - Energy from that class:
Ei = Pi · ti / 1000(MWh/yr)
Total annual energy:
Eyear = Σ Ei (reported in MWh and GWh).
Installed capacity (if turbine fully loaded at Qt,max):
Pinst = 9.81 · Qt,max · H · η (kW)
Capacity factor:
CF = Eyear / (Pinst · 8760 / 1000),
expressed as a fraction or percent.